X^2+63x-268=0

Solution for X^2+63x-268=0 equation:

X^2+63X-268=0

a = 1; b = 63; c = -268;
Δ = b2-4ac
Δ = 632-4·1·(-268)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-71}{2*1}=\frac{-134}{2}
=-67
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+71}{2*1}=\frac{8}{2}
=4
$